hi i am new at robot framework
i want to check button present in ui or not if present then performed certain operation
in else block i want write certain positive conditon means button is not visiable
${element}= Convert To String ${element.content}
IF ${element}
Should Be Equal ${element} ${Responce}
ELSE
Wait Until Element Is Not Visible ${loc__Validation}
Unselect Frame
END
in these condtion test get pass but if the if condtion fail that time else condtion can not run i want run else condition also
Thanks
hi @joseilton
${headers}= Create Dictionary Apikey=${apikey} Username=${userid}
Create Session session https://${environment}-api.${extension}
${response}= RequestsLibrary.GET On Session session ${premium_url} headers=${headers}
${responce1} Convert To String ${response.content}
${body} evaluate json.loads($edition) json
[Return] ${body}
# Get body as dict
${message} = Get From Dictionary ${body} bank_stock
Log To Console ${message} (output {‘stock’: ‘premium’})
${locator_checkbutton_} =//*[contains (text(),‘Check button’)]
in if block now i have write condition if stock is premium then check button is
visible
and in else condition is like if stock is not premium then check button is not visible
please help how to right it
Basically what joseiliton has provided is what you need to apply from the sounds of it… and you can make use of the Wait Until Element Is Visible or any of the other visible keywords
${chk_btn_is_visible}= Run Keyword and Return Status Wait Until Element Is Visible //foo
IF ${chk_btn_is_visible}
No Operation # YAY! Stock is premium.. do something
ELSE
No Operation # BOO...! Stock is not premium.. do something
END
or… as you’ve not really said if there’s a way to identify if a stock item is of type premium, you could do something like below:
IF {stock_is_premium}
Element Should Be Visible //foo Premium stock should show a check button, but the button doesn't show.
ELSE
Element Should Not Be Visible //foo None premium stock should not show the check button, but the button shows.
END